Respuesta :
[tex]\sin(\theta) = \dfrac{\text{opp}}{\text{hyp}}[/tex]
[tex]\sin(45) = \dfrac{6 \sqrt{2} }{x} [/tex]
[tex]x= \dfrac{6 \sqrt{2} }{\sin(45)} [/tex]
[tex]x= 12[/tex]
[tex]\sin(45) = \dfrac{6 \sqrt{2} }{x} [/tex]
[tex]x= \dfrac{6 \sqrt{2} }{\sin(45)} [/tex]
[tex]x= 12[/tex]
I believe the answer is D) 12\/-2 (I don't know how to write it with a normal keyboard. lol) Because sides A and B are both 6\/-2. A^2 + B^2 = C^2