Respuesta :
If the wild/normal gene is igf2 and the mutated gene is igf2-, then the genotype of the parent would be:
male: igf2 / igf2- ----> possible gametes: igf2 and igf2-
female: igf2 / igf2 ----> possible gamete: igf2
Then the cross result would be: 50% heterozygous for a mutant (igf2/igf2-) and 50% homozygous for the wild-type(igf2/igf2)
male: igf2 / igf2- ----> possible gametes: igf2 and igf2-
female: igf2 / igf2 ----> possible gamete: igf2
Then the cross result would be: 50% heterozygous for a mutant (igf2/igf2-) and 50% homozygous for the wild-type(igf2/igf2)
A male mouse that is heterozygous for a mutant igf2 allele (igf2/igf2-) is crossed with a female who is homozygous for the wild-type igf2 allele. The expected outcome of this cross would be fifty percent of homozygous wild type and fifty percent of heterozygous mutant species.
Further Explanation:
The allele that codes the particular phenotype which is most common in a population is called the wild type allele. Mutant allele is referred as different type of allele from wild type. Wild type is dominant in nature. A recessive trait is defined as a trait that gets expressed by an individual when they show a homozygous recessive condition. This means that if an individual showing a recessive trait will definitely possess both the recessive alleles for that trait as recessive trait gets concealed by the presence of allele for dominant trait.
If the wild/normal gene is igf2 and the mutated gene is igf2-, then the genotype of the parent would be:
- Male: igf2 / igf2, possible gametes: igf2 and igf2-
- Female: igf2 / igf2, possible gamete: igf2
Then the resultant cross gives fifty percent of heterozygous for a mutant (igf2/igf2-) and fifty percent of homozygous for the wild-type (igf2/igf2).
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Answer Details:
Grade: High School
Subject: Biology
Topic: Wild and mutant type
Keywords:
Male, female, homozygous, heterozygous, wild, mutant, allele, recessive, dominant, gene, trait, individual, genotype, phenotype, same, genetic makeup, organism.