Question

The rectangle shown has a perimeter of 62 cm and the given area. its length is 4 more than twice its width. write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

what is the area?

taking the length to be 2x+4 and the width to be x,

$62 = 2(2x + 4 + x)$
hence,
$6x = 54$
and thus
$x = 9$


that means the width is 9.
since we established that the length is (2x+4), we can substitute x=9 into the equation. hence,
$2x + 4 = 2(9) + 4 = 22$
therefore the length is 22

use the area to check your answer!