Question

Determine the pressure exerted by 2.50 mol of gas in a 2.92 l container at 32 oc.

Answer 1

I guess you meant "at $32^{\circ}C$"

Solution:
we can solve the problem by using the ideal gas law, which states:
$pV=nRT$
where
p is the gas pressure
V its volume
n the number of moles
R the gas constant
T the absolute temperature

Before using this equation, we have to convert the temperature in Kelvin:
$T=32^{\circ}C+273 = 305 K$
and the volume in $m^3$:
$V=2.92 L= 2.92 dm^3 = 2.92 \cdot 10^{-3} m^3$

So now we can re-arrange the ideal gas equation to find the pressure exerted by the gas, p:
$p= \frac{nRT}{V}= \frac{(2.50 mol)(8.31 J/mol K)(305 K)}{2.92 \cdot 10^{-3} m^3}= 2.17 \cdot 10^7 Pa$