Question

How many moles of gas occupy 98 l at a pressure of 2.8 atmospheres and a temperature of 292 k?

Answer 1

From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n =$\frac{PV}{RT}$ = $\frac{2.8 X 98}{0.082 X 292}$ = 11.46

Answer 2

"11.46" moles of gas occupy 98 L at 2.8 atm pressure.

Ideal gas equation:

The equation characterizing the stages of hypothetical gasses stated mathematically involving combinations of empirical as well as physiological constants, is considered as Ideal gas equation.

According to the question,

Volume occupied, V = 98

Temperature, T = 292 k

Pressure, P = 2.8 atm

By using ideal gas equation, we get

→ PV = nRT

or,

→ n = $\frac{PV}{RT}$

By substituting the above values, we get

      = $\frac{2.8\times 98}{0.082\times 292}$

      = $\frac{274.4}{23.944}$

      = $11.46$

Thus the above answer is appropriate.

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