Question

The vertex form of h(x) = x2 – 14x + 6 is h(x) = (x – )2 – .

Answer 1

The vertex form of h(x) = x2 – 14x + 6 is h(x) = (x –7 )2 –43 .
So 7and 43 are the answers

Answer 2

We will see that the vertex of the quadratic equation is (7, -43), so the vertex form is:

$h(x) = (x - 7)^2 - 43$

How to find the vertex form of the quadratic equation?

We have the quadratic equation:

$h(x) = x^2 - 14x + 6$

First, we need to find the vertex.

The x-value of the vertex is:

$x = -(-14)/(2*1) = 7$

To get the y-vale of the vertex, we need to evaluate the function in x = 7.

$h(7) = 7^2 - 14*7 + 6 = -43$

So the vertex is (7, -43), then the vertex form is:

$h(x) = (x - 7)^2 - 43$

If you want to learn more about quadratic equations:

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