Question

What is the angle of this triangle

Answer 1

$A_\Delta=\dfrac{1}{2}\sin65^o\cdot8\cdot12=48\sin65^o\\\\\sin65^o=0.9063\\\\P_\Delta=48\cdot0.9063=43.5024\approx43.5\ cm^2$

Answer 2

$\text{Given that the formula for Area is } \dfrac{1}{2} \text{ab} \sin(\text{c})$

$\text{Area = } \dfrac{1}{2} \text{(12)(8)} \sin(\text{65}\textdegree)$

$\text{Area = }43.5 \text{ cm}^2$