Question

If 21.3 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 297 Kelvin and 1.40 atmospheres? Show all of the work used to solve this problem.

2Li (s) + 2H2O (l) —> 2LiOH (aq) + H2 (g)

Answer 1

() = 2(2)
() =

=
21.3 6.94
= 3.07
( 2) = 1.53 (2) = (2)∗
At STP: = 22.4 /:
(2,) = 1.53∗22.4 = 34.4
At 297 K and 1.4 atm:

= ⇒
1∗34.4 273.15
=
1.40∗ 297
= 26.7


which means the answer is 26.7 liters