Question

A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and spring B has a spring constant of 5 N/m. How do the lengths of the springs compare?

Answer 1

The length(extension in spring, x), force applied (F) and the spring constant(k) are related by the following equation:

F = kx

For spring 1:
60 = 4x
so,
x = 15 m

For spring 2:
50 = 5x
so,
x = 10m

Thus the extension in length of second spring will be 5 meters more than the first spring