Question

you compared the two functions below. f(x) = 1.2t      g(x) = 1.2t-5
What did subtracting 5 in the exponent do to the function? Check all that apply.
A. It shifts the graph of f left 5 units.
B. It shifts the graph of f right 5 units.
C. It multiplies all the y-values by 5.
D. It divides all the y-values by 5.
E. It multiplies all the y-values by 1.25.
F. It divides all the y-values by 1.25.

Answer 1

the second and the last are the correct ones

Answer 2

Answer:

B. It shifts the graph of f right 5 units.

F. It divides all the y-values by 1.25.

Step-by-step explanation:

Let me revise your two functions:

f(x) = $1.2^{t}$

g(x) = $1.2^{t-5}$

So g(x) is the transformed function of f(x), as we know that

• if we subtract anything from x or t (independent variable), the graph will move right.

• if we add anything from x or t (independent variable), the graph will move left.

In this situation, we subtract 5 from it, so the graph of f right 5 units.

However, it also affect to the value of y, I will rewrite g(x)

g(x) = $\frac{1.2^{t} }{1.2^{5} }$ = $1.2^{t}$ *$\frac{1}{1.25^{5} }$ = $\frac{1}{1.25^{5} }$ f(x)