Question

Given log4(3) =0.7925 and log4(5) =1.1610, use log properties to find log4(240).

Answer 1

$\log_{4}(240)=\log_{4}(3 \cdot 4^{2} \cdot 5) = \log_{4}(3) +\log_{4}(4^{2}) +\log_{4}(5) = 0.7925 +2 +1.1610 = 3.9535$

$\log_{4}(240) \approx 3.9535$