[tex] \dfrac{x}{x+1} \ , \ \dfrac{7x}{x-1}[/tex]
[tex] \dfrac{x (x -1)}{(x+1)(x -1)} \ , \ \dfrac{7x(x+1)}{(x-1)(x+ 1)} [/tex]
We know that (a + b)(a - b) = a² - b²:
[tex]\dfrac{x (x -1)}{x^2 - 1}} \ , \ \dfrac{7x(x+1)} {x^2 - 1}[/tex]
Answer: LCD = ( x + 1) (x - 1)