Respuesta :

the answer is six remainder three

A video store has 27 new release movie posters.

the manager choose a group of 4 for a prize.

When we choose a group of 4, the order does not matters.

So we use combination

We need to find 4 from 27 new release movie posters.

27C4

nCr = [tex]\frac{n!}{r!(n-r)!}[/tex]

27C4 = [tex]\frac{27!}{4!(27-4)!}[/tex] = [tex]\frac{27!}{4!(23!)!}[/tex]= 17550

The manager can choose a group of 4 for a prize in 17,550 ways.


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