Question

HELP!!!! ASAP

A ladder leans against a building, making a 70 angle of elevation with the ground. The top of the ladder reaches a point on the building that is 39 feet above the ground. To the nearest tenth of a foot, what is the distance between the base of the building and the base of the ladder?

Answer 1

$\tan \theta = \dfrac{opp}{adj}$

$\tan 70^\circ = \dfrac{39~ft}{x}$

$x \tan 70^\circ = 39~ft$

$x = \dfrac{39~ft}{\tan 70^\circ}$

$x = 14.1948...~ ft$

$Answer: 14.2~ft$