The center of a circle of the form:
[tex](x-a)^{2}+(y-b)^{2}=r^{2} [/tex]
is (a, b) and its radius is r.
Comparing the given equation of circle we can write:
a = 20
b = 0.05
r² = 81
This means the center of the circle is (20, 0.05) and the radius of the circle is 9.
