Respuesta :
I find it easiest to start with the 2-point form of the equation of a line.
y = (y₂-y₁)/(x₂-x₁)*(x-x₁) +y₁
where the given points are (x₁, y₁) and (x₂, y₂).
Substituting the given numbers, you have
y = (8 -4)/(3 -(-1))*(x -(-1)) +4
y = 4/4(x +1) +4
y = x +5
The desired slope-intercept form of the equation for the line is ...
y = x + 5
y = (y₂-y₁)/(x₂-x₁)*(x-x₁) +y₁
where the given points are (x₁, y₁) and (x₂, y₂).
Substituting the given numbers, you have
y = (8 -4)/(3 -(-1))*(x -(-1)) +4
y = 4/4(x +1) +4
y = x +5
The desired slope-intercept form of the equation for the line is ...
y = x + 5

Slope is change in y over change in x, which is 1.
The equation is y=mx+b, but we only know the slope. We need the y-intercept now.
y=x+b (1x can be written as x)
b=5.
The equation is y=x+5.
