Question

Evaluate C(5, 0)
A.0
B.1
C.5

Answer 1

There is 1 way to choose none of 5. The appropriate choice is
  B. 1


_____
C(n, k) = n!/(k!(n-k)!)
C(5,0) = 5!/(0!(5-0)!) = 1/0! = 1/1 = 1 . . . . . 0! ≡ 1.

Answer 2

Answer:

C(5, 0) = 1

B is the correct option.

Step-by-step explanation:

We have to find the value of C(5, 0).

The formula for combination is given by

$C(n,r)=\frac{n!}{r!(n-r)}!$

Here, we have

n = 5

r = 0

Thus, we have

$C(5,0)=\frac{5!}{0!(5-0)!}$

We know that 0! = 1. Thus, we have

$C(5,0)=\frac{5!}{1\cdot5!}\\\\C(5,0)=1$

Therefore, we have C(5, 0) = 1

B is the correct option.