Respuesta :
The answer to this question is B. (sqrt 2, 315 degrees). This polar coordinate is the only coordinate with its angle in quadrant 4 and a length of √1^2 + (-1)^2 = √2.
Answer:
The polar coordinate is [tex](\sqrt{2},315^\circ)[/tex]
B is correct
Step-by-step explanation:
Given:
Rectangular coordinates: (1,-1)
We need to change into polar coordinate.
Cartesian to polar change rule:
[tex](x,y)\rightarrow (r,\theta)[/tex]
[tex]x=r\cos\theta[/tex]
[tex]y=r\sin\theta[/tex]
[tex]\text{Where, }r=\sqrt{x^2+y^2}\text{ and }\theta=\tan^{-1}\dfrac{y}{x}[/tex]
[tex]=r=\sqrt{1+1}=\sqrt{2}[/tex]
[tex]\sqrt{2}\cos\theta=1[/tex]
[tex]\sqrt{2}\sin\theta=-1[/tex]
Cosine is negative and Sine is positive.
Thus, angle lie in IV quadrant.
[tex]\theta=\tan^{-1}(-1)[/tex]
[tex]\theta=360-45=315^\circ[/tex]
Cartesian to polar
[tex](1,-1)\rightarrow (\sqrt{2},315^\circ)[/tex]
Hence, The polar coordinate is [tex](\sqrt{2},315^\circ)[/tex]