Question

NEED HELP WITH A MATH QUESTION!! WILL MARK BRAINLIEST IF CORRECT

This rectangular prism is intersected by a plane that contains points D, E, K, and L.

What is the perimeter of the cross section?

Enter your answer in the box. Round only your final answer to the nearest tenth.

____ m

Answer 1

4^2 + 5^2 = EK^2
16 + 25 =
41 = EK^2
EK = square root of 41

12 + 12 + square root of 41 + square root of 41 = perimeter

24 + 2(square root of 41)

About 36.8

Hope it's right

Answer 2

The perimeter of the cross section is 36.8 m.

What is the perimeter of the rectangle?

The perimeter of a rectangle is, P = 2 × (length + width)

For given example,

We need to find the perimeter of the cross section.

The cross section would be rectangle with sides DE, EK, KL, DL

where, DE, KL represents length of the cross section and DL, EK represents width of the cross section.

To find the length of EK,

$EK^2=EJ^2+JK^2\\\\EK^2=5^2+4^2\\\\EK^2=25+16\\\\EK^2=41\\\\EK=\sqrt{41}~m$

So, DL = √41 m

DE = KL = 12 m

The perimeter of the cross section is:

$P=2 \times (12+\sqrt{41} )\\\\P=2\times (12+6.403)\\\\P=2 \times 18.403\\\\\bold{P=36.8~m}$

Read more about the perimeter of rectangle here:

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