a train moving west with an initial velocity of 20m/s accelerates 4m/s2 for 10 seconds . during this time , the train moves a distance of

Respuesta :

arshin
x=1/2at^2+vt+x0
x=1/2(4)(100)+20(10) = 400 m

When a  train moving west with an initial velocity of 20m/s accelerates 4m/s² for 10 seconds during this time, the train moves a distance of 400 m.

What are the three equations of motion?

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

where u and v are the initial and final velocity respectively

S is the total distance covered by the object

a is the acceleration of the object

As given in the problem a train moving west with an initial velocity of 20m/s accelerates 4m/s² for 10 seconds by using the second equation of motion

S = ut + 1/2*a*t²

u= 20 m/s , a= 4 m/s² and t = 10 seconds

S = 20*10 + 0.5*4*10²

S = 200+200

S= 400 m

Thus, the train covers a distance of 400 meters.

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