Question

A right triangle has a leg of 5 inches and a hypotenuse of 7 inches. What is the length of the other leg?

Enter your answer, as a decimal rounded to the nearest tenth, in the box.

Answer 1

a² + b²  = c²

a² = 7² - 5²

a² = 24

a = √24

a = 4.9 inches (nearest tenth)

Answer: 4.9 inches

Answer 2

Answer:

$(Base)=\sqrt{24} {\text{inches}$

Step-by-step explanation:

It is given that A right triangle has a leg of 5 inches and a hypotenuse of 7 inches, thus using the trigonometry, we have

$(Hyp)^2=(Base)^2+(Per)^2$

Substituting the given values, we have

$(7)^2=(Base)^2+(5)^2$

⇒$49=(Base)^2+25$

⇒$49-25=(Base)^2$

⇒$24=(Base)^2$

⇒$(Base)=\sqrt{24} {\text{inches}$

Thus, the length of the other leg is $\sqrt{24} {\text{inches}$.