Respuesta :
Since, a line segment TV has endpoints at (2,10) and (18,-18).
We have to determine the length of this line segment.
We will use distance formula for finding this length, which states:
For given points [tex] (x_{1},y_{1}) [/tex] and [tex] (x_{2},y_{2}) [/tex]
Distance(Length) = [tex] \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}} [/tex]
So, length of line segment TV
= (2, 10) and (18,-18)
[tex] x_{1}=2 , y_{1}=10 , x_{2}=18 ,y_{2}= -18 [/tex]
Length of TV = [tex] \sqrt{(18-2)^{2}+(-18-10)^{2}} [/tex]
= [tex] \sqrt{(16)^{2}+(-28)^{2}} [/tex]
[tex] =\sqrt{(256+784)} [/tex]
=[tex] \sqrt{1040} [/tex]
= 32.249 units
= 32.25 units
So, the length of the line segment TV is 32.25 units.
