Question

If x and y are real numbers what is the simplified radical form of x^2y^5

Answer 1

x, y ∈ R

$x^{2}y^{5}\\\\ \sqrt{x^{2}y^{5}} = \sqrt{x^{2}*y*y^{4}}= \sqrt{x^{2}*y*({y^{2})^{2}} }=xy^{2} \sqrt{y}$

Answer 2

The simplified radical form of the expression x^2y^5 will be $x^{10y}$.

What are real numbers?

A real number is a value of a quantity that can represent a distance along a line. It can be in the form of decimal or not in decimal numbers. It can be integers, rational, irrational, fractions, etc.

How to simplify real numbers?

If x and y are real numbers then the simplified radical form of x^2y^5 as under:

because it is given the power of power for that we have to multiply both the powers.

$x^{2y} ^{5}$=$x^{10y}$

Hence the simplified radical form of the expression is $x^{10y}$.

Learn more about real numbers at https://brainly.com/question/155227

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