Question

PLEASE HELP ASAP

a rectangular garden has length three times as great as its width a second rectangular garden has the same width as the first garden and length that is 3 meters greater than the length of the first garden the second garden has area of 90 square meters

what is the width of the two gardens?

Answer 1

Let,
L1,B1 be the length & width of first garden
L2,B2 be the length & width of second garden
Given ,
L1 = 3 (B1) 
B1 = B2
L2 = L1+3 &
L2* B2 = 90
So,(L1+3)*B1 = 90
(3(B1)+3)*B1= 90
By solving,
B1= 5
So, B1=B2=5
L1= 3*5 = 15
L2= 3+15 =18

Answer 2

Answer:

5 meters

Step-by-step explanation:

First Rectangle :

Let the width = x

Given that length of the garden is 3 times that of width

Length = 3x

Second Rectangle:

As the width of both the rectangle is same

Width = x

Also given that the length of second rectangle is 3 meters more than that of first rectangle

Length = 3x+3 = 3(x+1)

Also given that Area = 90

Area = length * width

$90=x *3(x+1)\\90=3x(x+1)\\30=x^2+x\\x^2+x-30=0\\x^2+6x-5x-30=0\\x(x+6)-5(x+6)=0\\(x-5)(x+6)=0$

Hence either

x-5=0 or x=5

or

x+6=0 making x=-6 which is not possible as width can not be negative

Hence the width of the gardens is 5 meters