4x + 5y = 22. ... equation 1
2x + 3y = 12. ... equation 2
Multiple equation 2 by 2, and subtracte equation 1 from it, we get.
=> 4x + 6y - (4x + 5y) = 24 - 22
=> y = 2
Now, put the value of y in equation 1, we get
=> 4x + 5(2) = 22
=> 4x = 12
=> x = 3
So, Ans : (3,2). (option A)
Hope this helps!