Given => 3x + y = 10. .. equation 1
y = x - 2. ... equation 2
Putting value of y from equation 2 to equation 1, we get
=> 3x + (x - 2) = 10
=> 4x - 2 = 10
=> x = 3
Put the value of x in equation 2
=> y = 3 - 2
=> y = 1
Ans : (3, 1). (Option D)
Hope this helps!