Respuesta :
The Ph of a solution with (H3O+) = 5.9 x10 ^-3M is calculated as below
Ph= - Log (H3O+) concentration
that is Ph= -Log ( 5.9 x10^-3) = 2.2
the solution is acidic since the Ph is less than 7
Ph= - Log (H3O+) concentration
that is Ph= -Log ( 5.9 x10^-3) = 2.2
the solution is acidic since the Ph is less than 7
pH is related to [H₃O⁺] as follow,
pH = -log [H₃O⁺]
As,
[H₃O⁺] = 5.9 × 10⁻³
Putting this value in above equation,
pH = -log (5.9 × 10⁻³)
pH = 2.23
Result:
As the pH of given concentration of H₃O⁺ ions is less than 7, so it is acidic in nature.
pH = -log [H₃O⁺]
As,
[H₃O⁺] = 5.9 × 10⁻³
Putting this value in above equation,
pH = -log (5.9 × 10⁻³)
pH = 2.23
Result:
As the pH of given concentration of H₃O⁺ ions is less than 7, so it is acidic in nature.