Respuesta :

Lewis Structure of Oxygen Difluoride is sketched as....

Step 1:
           Calculate the total number of valence electrons present in OF₂. This is done by adding all valence electrons of each element. i.e...

Valence e⁻s of Oxygen      =  6

Valence e⁻s of Fluorine-1  =  7

Valence e⁻s of Fluorine-2  =  7
                                           ------------
Total Valence e⁻s                   20

Step 2:
           Draw central element (O) in center surrounded by fluorine atoms. Now, sketch a single bonds between O and both F atoms. Now, subtract 2 electrons per single bond from total valence electrons.. i.e..

Total Valence e⁻s         =  20
2 single bonds (2 × 2)  =    4
                                     -----------
                                         16

Now, distribute remaining 16 electrons on each element to complete its octet starting from most electronegative element.

Lewis structure of OF₂ is as follow,
Ver imagen transitionstate
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