Question

hey can you please help me posted picture of question

Answer 1

The vertex of a quadratic function can be calculated as:

$(- \frac{b}{2a},y( \frac{-b}{2a})$

b = coefficient of x term = 10
a = coefficient of squared term = 1

So,

$- \frac{b}{2a}=- \frac{10}{2}=-5 \\ \\ y( \frac{-b}{2a})=y(-5) \\ \\ =(-5)^{2} +10(-5)+24 \\ \\ =-1$

Thus, the coordinates of vertex for the given parabola are (-5, -1)

So, option C is the correct answer.

Answer 2

The answer is C.

To find the vertex, you must use -b/2a. -10/2, which -5 and is also the variable x. Now that we have x, you must plug in -5 to the original quadratic equation to find y.

 y = (-5)^2 + 10(-5) + 24

25 + (-50) +24 = -1

x = -5
y = -1

C.