Question

what is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?

Answer 1

Answer:

(x+2)²+(y+4)²=169

Step-by-step explanation:

In simplest terms

Answer 2

The radius of a circle that its center is at (-2,-4), and passes through point (3, 8) is $(x + 2)^2 + (y + 4)^2 = 169$

How to determine the circle equation?

The given parameters are:

• Center, (a,b) = (-2,-4)
• Point, (x,y) = (3,8)

The length of the radius is calculated using:

$r = \sqrt{(x - a)^2 + (y - b)^2}$

So, we have:

$r = \sqrt{(3 + 2)^2 + (8 + 4)^2}$

Evaluate

$r = \sqrt{169}$

Square both sides

$r^2 = 169$

The equation of the circle is calculated using:

$(x - a)^2 + (y - b)^2 = r^2$

So, we have:

$(x + 2)^2 + (y + 4)^2 = 169$

Hence, the equation of the circle is $(x + 2)^2 + (y + 4)^2 = 169$

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https://brainly.com/question/1559324

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