We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7
Using the values, we get:
[tex]x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\
x= \frac{-4+- \sqrt{-12} }{2} \\ \\
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\
x= -2+- \sqrt{-3} [/tex]
So, the correct answer to this question is option A
