We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15
Using the values, we get:
[tex]x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\
x= \frac{11+-1}{4} \\ \\
x=3, x= 2.5 [/tex]
So, the correct answer to this question are option B and D
