The relationship between Sabir and calories he burns can be modeled using a linear function given by:
y=ax+b
where
a=slope
b=y-intercept
from the graph, the slope will be given as follows:
taking points (3,15) and (12,60)
a=(60-15)/(12-3)=5 calories/minute
thus using the slope and a point (3,15) the equation will be:
a(x1-x)=(y1-y)
plugging the values we obtain:
5(x-3)=y-15
5x-15=y-15
thus
y=5x
thus the equation is:
y=5x
