The function f(z) is defined for z in [1, 6]. We want to find x such that
z = 3(x -2)
Substituting the interval for z, we have
[1, 6] = 3(x -2)
[1/3, 2] = x -2 . . . . divide by 3
[2 1/3, 4] = x . . . .. add 2
The domain of f(3(x -2)) is ...
2 1/3 ≤ x ≤ 4.