Only 40% of the students in a certain liberal arts college are males. if two students from this college are selected at random, what is the probability that they are of the same gender?

Respuesta :

p(mm) = 40/100 x 40/100 = 4/25

p(ff) = 60/100 x 60/100 = 9 /25

4/25 + 9/25 

= 13/25

The Probability of  the students are of the same gender 13/25.

What is Probability?

Probability is "possibility of the outcome of any random event".

According to the question,

Probability of the students are males P(m) = [tex]\frac{40}{100}[/tex] = [tex]\frac{2}{5}[/tex]

Probability of the students are females P(f) = [tex]\frac{60}{100}[/tex] = [tex]\frac{3}{5}[/tex]

Probability of the students both are males P(mm) = [tex]\frac{2}{5}[/tex] × [tex]\frac{2}{5}[/tex] = [tex]\frac{4}{25}[/tex]

Probability of the students both are males P(ff) = [tex]\frac{3}{5}[/tex] × [tex]\frac{3}{5}[/tex] = [tex]\frac{9}{25}[/tex]

In order to find, the probability of same gender, add P(mm) and P(ff) we get,

= [tex]\frac{4}{25}[/tex] + [tex]\frac{9}{25}[/tex]

= [tex]\frac{13}{25}[/tex]

Hence, The Probability of  the students are of the same gender 13/25.

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