Respuesta :
Let's say that the genotype of the couples are:
Cc and Cc. Notice that one is capital and the other is not. This is what shows that they are heterozygous. We put this now in a Punnet Square:
C c
C CC Cc
c Cc cc
This means that there is a 75% chance that their children will have a cleft-chin and 25% will not.
The probability is the same with each off-spring. So the answer would be 75% chance the same probability for all subsequent children.
Cc and Cc. Notice that one is capital and the other is not. This is what shows that they are heterozygous. We put this now in a Punnet Square:
C c
C CC Cc
c Cc cc
This means that there is a 75% chance that their children will have a cleft-chin and 25% will not.
The probability is the same with each off-spring. So the answer would be 75% chance the same probability for all subsequent children.