Respuesta :
speed of current ------ y km/h
distance with the current = 4(x+y)
distance against the current = 5(x-y)
we know that 3.5(x+y) = 70
x+y = 20
but 4(x+y) = 4(20) = 80
then 5(x-y) = 80
x-y = 16
x+y=20
x-y=16
add them
2x = 36
x = 18 , then y = 2
distance with the current = 4(x+y)
distance against the current = 5(x-y)
we know that 3.5(x+y) = 70
x+y = 20
but 4(x+y) = 4(20) = 80
then 5(x-y) = 80
x-y = 16
x+y=20
x-y=16
add them
2x = 36
x = 18 , then y = 2
The speed of the boat in still water is mathematically given as
x = 18 , y = 2
What is the speed of the boat in still water?
Question Parameter(s):
the distance from one pier to the other pier in 4 hours and the way back in 5 hours
if it covers 70 km
with the current in 3.5 hours?
Generally, the equation for the speed of the current is mathematically given as
d1 = 4(x+y)
d2 = 5(x-y)
3.5(x+y) = 70
x+y = 20
therefore,
4(x+y) = 4(20) = 80
5(x-y) = 80
In conclusion the speed of the boat in still water
x+y=20
x-y=16
2x = 36
x = 18 , y = 2
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