Question

How would you expand log412 so that it can be evaluated, given log43 ≈ 0.792?

Answer 1

the answer is C just guessed and i got it right.

Answer 2

Answer:

C. log₄3+log₄4

Second Answer: C. $log_{7}36$

Third Answer: B. $log_{h} 9+log_{h} j+log_{h} k$

Step-by-step explanation:

Got it right.