Respuesta :
To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
Short answer <<<< C
The length of an arc is given by the formula
[tex]\text{Arc length =}\dfrac{\theta}{2\pi}{2 \pi r} [/tex]
Since the arc length is given (4 [tex] \pi [/tex]) and the radius is given (6), the central angle [tex] \theta[/tex] can be found
Arc Length = theta * r
4 pi = theta * 6 Divide by 6
4 pi / 6 = theta
theta = (2/3) pi <<<<<< answer.
Answer C <<<<<< answer.
The length of an arc is given by the formula
[tex]\text{Arc length =}\dfrac{\theta}{2\pi}{2 \pi r} [/tex]
Since the arc length is given (4 [tex] \pi [/tex]) and the radius is given (6), the central angle [tex] \theta[/tex] can be found
Arc Length = theta * r
4 pi = theta * 6 Divide by 6
4 pi / 6 = theta
theta = (2/3) pi <<<<<< answer.
Answer C <<<<<< answer.