m3rk098 m3rk098
  • 28-04-2018
  • Mathematics
contestada

hey can you please help me posted picture of question

hey can you please help me posted picture of question class=

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boiscutie
boiscutie boiscutie
  • 28-04-2018
i believe it is b. it has one real solution 
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carlosego
carlosego carlosego
  • 28-04-2018
We have the resolvent is:
 x = (- b +/- root (b2 - 4ac)) / (2a)
 The discriminant is:
 b2 - 4ac> 0
 Therefore, the root is positive.
 Thus, the equation has two real solutions.
  x1 = (- b + root (b2 - 4ac)) / (2a)
  x2 = (- b - root (b2 - 4ac)) / (2a)
 Answer:
 
option C
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