PLEASE HELP!! SO IMPORTANT! The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70cm^3 of water. Find the percent of the cup that is filled with water after 3 seconds. Use 3.14 for pi and round your final answer to the nearest percent.

Respuesta :

Note : The dimensions of the cup are not given.

Now we have been given that, after 2 seconds, the cup has a volume of 70 cubic cm.

As the cup is filled at a constant rate, in 1 second, it fills

[tex]\frac{70}{2}=35[/tex] = 35 cubic cm.

Hence, in 3 seconds, it fills [tex]35\times3=105[/tex] cubic cm.

To find the percent we need the dimensions of the cup.

The percentage of the cup that is filled with water after 3 seconds is 105 cm^3.

What is the unitary method?

The unitary method is a process by which we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

The cup was filled at a constant rate. it started empty. after 2 seconds, it held 70 cm of water.

The cup was filled at a constant rate.

first, we will find the volume of water filled in the cup after 1 second.

2 seconds =  70  water

1 second = Volume of water filled in 1 second.

By Using the Unitary method we get;

The volume of water filled in 1 second = 70/2 = 35

Now we will find the volume of water filled in the cup after 3 seconds.

1 second =  35  of water is filled

3 seconds = volume of water filled in the cup after 3 seconds.

The volume of water filled in the cup after 3 seconds = [tex]35\times 3=105[/tex].

Hence, the percentage of the cup that is filled with water after 3 seconds is 105 cm^3.

Learn more about the unitary method here;

brainly.com/question/9794527

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