Question

According to the fundamental theorem of algebra how many roots exists for the polynomial function (9x+7)(4x+1)(3x+4)=0

Answer 1

16x + 7 +1 +4 =0
16x +12=0
-12 -12
16x = -12
16. 16
x = -0.75
answer is 3

Answer 2

Answer:

Step-by-step explanation:

According to the fundamental theorem of algebra a polynomial of degree n will have n roots

The degree of a polynomial is the largest number to which the variable is raised

We have the factored polynomial

To know what the degree of the polynomial is we have to apply the distributive property and see which is the largest number to which the x is raised

we apply distributive property

$(9x+7)(4x+1)(3x+4)\\ 36x^2+9x+28x+7(3x+4)\\108x^3+27x^2+84x^2+21x+432x^2+36x+112x+28$

the largest number to which the x is elvolved is 3 therefore (According to the fundamental theorem of algebra) the polynomial will have 3 roots