Question

hey can you please help me posted picture of question

Answer 1

We have the following equation:
 x2-5x + 1 = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 Substituting values we have:
 x = (- (- 5) +/- root ((- 5) 2 - 4 (1) (1))) / 2 (1)
 Rewriting:
 x = (5 +/- root (25 - 4)) / 2
 x = (5 +/- root (21)) / 2
 The results are:
 x = (5 + root (21)) / 2
 x = (5 - root (21)) / 2
 Answer:
 x = (5 + root (21)) / 2
 x = (5 - root (21)) / 2
 option D and E

Answer 2

The equation is:  x2-5x + 1 = 0  Here we can say that this is a quadratic equation so we must find x using the formula of a quadratic equation which is:  x = (- b +/- root (b2 - 4ac)) / 2a   Substitute the values :  x = (- (- 5) +/- root ((- 5) 2 - 4 (1) (1))) / 2 (1)  x = (5 +/- root (25 - 4)) / 2  x = (5 +/- root (21)) / 2   Which is equal to=  x = (5 + root (21)) / 2  x = (5 - root (21)) / 2 So the answers would be D and E