Question

hey can you please help me posted picture of question

Answer 1

We have the following equation:
 ax2 + bx + c = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 We have:
 b2 - 4ac <0
 Therefore the root is negative
 Answer:
 It has two complex solutions
 option B

Answer 2

When the discriminant is lesser than zero then b. It has two complex solns