Respuesta :
The solubility of the molecule depends upon the polarity of the molecule as "Like dissolves Like" implies that polar molecule dissolves in polar solvent and non-polar molecule dissolves in non-polar solvent.
Iodine is a non-polar molecule and carbon disulfide is also a non-polar molecule as net dipole moment is equal to zero but water is a polar molecule as net dipole moment is not equal to zero. Since, non-polar compounds are soluble in non-polar. Thus, iodine is soluble in carbon disulfide instead of water because water is a polar molecule.
The solubility of any substance depends on the polarity of the molecule and implies that the like particle dissolves the like particle. Polar solute dissolves in the polar solvent and likewise, the non-polar solute dissolves in the non-polar solvent.
Iodine is soluble in carbon disulfide [tex]\rm (CS_{2})[/tex]
How the solubility of the Iodine can be explained as?
Iodine is a non-polar molecule and water is a polar molecule. When both are mixed then the net dipole moment will not be equal to zero and it will not be completely soluble.
Carbon disulfide is a non-polar molecule and will interact with the non-polar iodine molecule as their net dipole will be zero and will be soluble.
Therefore, iodine is soluble in carbon disulfide.
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