Question

The initial concentration of reactant in a first-order reaction is 0.27 m. the rate constant for the reaction is 0.75 s-1. what is the concentration (mol/l) of reactant after 1.5 s?

Answer 1

The concentration in  mol/l  of reactant  after  1.5 s  is calculated as  follows

from  first order  integrated  equation

 In (A)t  = - Kt + In (A)o  where
  At = final  concentration =?
A)o =initial  concentration =0.27 M
K =  constant=0.75
T=temperature =  1.5 s

in( A)t = -0.75(1.5) + in(0.27)

In (A)t =-1.125  +-1.31 =-2.435
In(A)t =-2.435

In (A)t  =  e
find the e  value 

 ( A)t is therefore =0.0876  mol/l

Answer 2

The final concentration of the reactant after 1.5 s has been 0.0876 mol/L.

The rate reaction for the first order reaction has been given by:

log [Initial concentration] = - rate constant $\times$ time + log [Final concentration]

The given reaction has:

Initial concentration = 0.27 M

Rate constant = 0.75/s

Time = 1.5 s

The final concentration can be given by:

log [0.27] = - 0.75 $\times$ 1.5 + log [Final concentration]

log [0.27] = - 1.125 + log [Final concentration]

log [Final concentration] = - 1.125 - log [0.27]

log [Final concentration] = - 1.125 + (-1.31)

log [Final concentration] = - 2.435

Final concentration = 0.0876 mol/L

The final concentration of the reactant after 1.5 s has been 0.0876 mol/L.

For more information about first order reaction, refer to the link:

https://brainly.com/question/12209424