Question

The electrolysis of molten alcl3 for 3.25 hr with an electrical current of 12.0 a produces ________ g of aluminum metal.

Answer 1

The correct answer is: 13.09g

Explanation:

Formula to find the mass of the deposited metal = W = $\frac{ECt}{96500}$

Where
E = Equivalent mass of Aluminum = Atomic-mass/valency = 27/3 = 9
C = Current = 12.0 A
t = time taken = 3.25hr = 3.25*60*60 = 11700s

Plug in the values in the formula:
W = $\frac{9*12*11700}{96500} = 13.09g$