Question

Mr. white ordered pizza for the party. medium pizzas have 8 slices and large pizzas have 10. if there are 13 pizzas and 108 slices, how many medium pizzas are there?

Answer 1

Let x and y be the number of medium and large pizzas respectively. Therefore,
x+y = 13 ------- (1)
8x+10y = 108 ------- (2)
--------------------------------
Solving (1) and (2)

From (1), x = 13 -y

Substituting in (2)

8(13-y)+10y = 108
104 - 8y +10 y =108
2y = 4 => y = 2
And then,
x= 13-y => 13 - 2 = 11

Therefore, there are 11 medium pizzas

Answer 2

The number of small pizzas and the large pizzas that Mr.white ordered are 11 and 2.

What is an equation?

An equation is formed when two expressions are equated with the help of an equal sign "=".

Let the number of small size pizzas be x, and the number of large size pizzas is y. Therefore, the total number of pizzas can be written as,

$x + y = 13$

We know that the number of slices that are in the smaller pizza is 8, while the number of slices that are in the large size pizza is 10. Also, the total number of slices where 108 slices, thus, the number of slices can be written as,

$8x + 10y = 108$

As we got the two equations, therefore, the solving the two equations,

$x + y = 13\\y = 13-x$

Substitute the value of y in the second equation,

$8x + 10y = 108\\\\8x + 10(13-x) = 108\\\\8x + 130 - 10x = 108\\\\-2x = -22\\\\x = 11$

Substitute the value of x in the first equation,

$x + y = 13\\\\11 + y = 13\\\\y=2$

Hence, the number of small pizzas and the large pizzas that Mr.white ordered are 11 and 2.

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