Question

Determine the sum: (14abc^2 + 12a^2b + 16b^2c) + (-3abc^2 + 2b^2c)

Answer 1

$(14abc^2 + 12a^2b + 16b^2c) + (-3abc^2 + 2b^2c)$

$= 14abc^2 + 12a^2b + 16b^2c - 3abc^2 + 2b^2c$

$= 11abc^2 + 12a^2b + 18b^2c$