Question

what is the solution set for square root of 3y+4=5
$\sqrt{3y } + 4 = 5$

Answer 1

We can solve it algebraically:
$\sqrt{3y} +4-4=5-4$ (subtract 4 from both sides to isolate $\sqrt{3y}$
$( \sqrt{3y})^{2} = (1)^{2}$ (square both sides to get rid of square root on left side
$3y/3=1/3$ (divide both sides by 3 to isolate y)
$y= \frac{1}{3}$